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6 years ago
If 1111=R, 2222=T, 3333=E, 4444=N Then 5555=?
6 years ago
The answer to this question is Y.
The logic followed here is determining the last letter of the number obtained on adding all the digits.
1111 = 1+1+1+1 = FOUR = R
2222 = 2+2+2+2 = EIGHT = T
3333 = 3+3+3+3 = TWELVE = E
4444 = 4+4+4+4 = SIXTEEN = N
5555 = 5+5+5+5 = TWENTY = Y