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8Â years, 9Â months ago
how to find cubes easily
8Â years, 8Â months ago
hey satya, let us assume the ten's place number of the given number as x and the unit's place number as y.......
after that taking the number....
Now, we all know that (x+y)^3=(x^3) + {3(x^2)(y)} + {3(x)(y^2)} + (y^3)