How many 5 digit no.'s can be formed by using the digits 0,1,2,4,8 only once so that they are divisible by 120?

since it has to divided by 120 the last digit should be 0. so cancelling the zero's we have number of 4 digit numbers formed by 1,2,4,8 that can be divide by 12. 12= 3*4. 1+2+4+8=15 so divisible by 3. in order to be divisible by 4 the last 2 digits must be divisible by 4. so 12,18,21,24,42,48,81,84. should be last and the first 2 digits can be arranged in 2 ways each. so 8*2=16