from a point P which is at a distance of 13 cm from centre O of a circle of radius 5 cm in the same plane a pair of tangents PQ and PR are drawn to the circle Area of quadrilateral PQOR

Question

Answer 1

60 sq.cm

Solution:

PO=13 (hypotenuse)
OQ=5
PQ=√PQ^2-OQ^2=12
Area of quadrilateral=Area of triangle POQ+POR
(And POQ=POR. CONGRUENT)
Area of POQ=1/2*5*12=30 (Area of right angle triangle=1/2*a*b)
AREA OF QUADRILATERAL PQOR=2*POQ=2*30= 60

Answer 2

60 sq.cm

Solution:

PO=13 (hypotenuse)
OQ=5
PQ=√PQ^2-OQ^2=12
Area of quadrilateral=Area of triangle POQ+POR
(And POQ=POR. CONGRUENT)
Area of POQ=1/2*5*12=30 (Area of right angle triangle=1/2*a*b)
AREA OF QUADRILATERAL PQOR=2*POQ=2*30= 60

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from a point P which is at a distance of 13 cm from centre O of a circle of radius 5 cm in the same plane a pair of tangents PQ and PR are drawn to the circle Area of quadrilateral PQOR