Reaction with active metals: $$2\text{R--OH} + 2\text{Na} \to 2\text{R--ONa} + \text{H}_2\uparrow$$
Acidity Order: $$\text{H}_2\text{O} > \text{CH}_3\text{OH} > 1^\circ > 2^\circ > 3^\circ \text{ alcohol}$$ (due to +I effect of alkyl groups destabilizing alkoxide ion).