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For how many values of p ; is 1000!/( p^p) completely divisible where p is a prime number?
the answer of the question is 25 Explanation, X^2=1000 then x = 100 so check all prime no that lies below 100 i.e.; 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 therefore total value is 25<br>
