Find the minimum length of the string to be wound around a cylinder of length 48 cm and circumference 16 cm such that the string takes 4 turns and its two ends touch the end and bottom of the cylinder?

Hi Vinatha,

In problems like these, finding the length of the string is equivalent to finding four times the hypotenuse of a triangle with base 16 cm and height 12 (48/4) cm.

Therefore, hypotenuse of triangle with base 16 cm and height 12 cm = $$\sqrt{16^2 +12^2}$$ = 20 cm

Therefore, the lenght of the string = 20*4 = 80 cm.

Hope this helps.

Thank you.