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4Â years, 11Â months ago
find the greatest number of four digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainders respectively.
4Â years, 11Â months ago
323 is answer because
l.c.m of 10,11,15,22 is= 330
and they remains 7(10-3,11-4,15-8,22-15)
330-7=323
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