find the greatest number of four digits which when divided by 10,11,15 and 22 leaves 3,4,8 and 15 as remainders respectively.

Question

Bhavesh Dhera · Answer

330K - 7
Largest : 9893

Mohan Babu · Answer

323 is answer because 
l.c.m of 10,11,15,22 is= 330
and they remains 7(10-3,11-4,15-8,22-15)
330-7=323

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