An alloy contains 70% zinc and 30% copper. In another alloy zinc is 78.5% and copper is 13%. In what ratio should both alloys be mixed so that the newly formed alloy contains 18% copper and also find the percentage of zinc in this.

Question

shivani s · Accepted Answer

Let amount of alloy 1 be X and alloy 2 be Y.
Amount of copper = 0.3X + 0.13Y. This is equal to 0.18(X+Y).
Solving we get X/Y as 5/12 which is the required ratio.
Percentage zinc = (0.7x5 + 0.785x12)/(5+12) = 0.76 = 76%

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An alloy contains 70% zinc and 30% copper. In another alloy zinc is 78.5% and copper is 13%. In what ratio should both alloys be mixed so that the newly formed alloy contains 18% copper and also find the percentage of zinc in this.