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Two friends A and B run on a 550 m circular track such that A (who is faster) overtakes B in the middle of A's 6th round for the first time.If they were to run on a stright track of length 10000 m, find approximately how much headstart A can give to B such that they finish the race at the same time?
A 1818m B 1837m C 1762m D 1265m

[SOLUTION] Since A overtakes B in the middle of the 6th round,B must be in the middle of the 5th round. So A has covered 5.5 times the track length while B has covered 4.5 times the track length. For every 5.5m covered by A,B covers 4.5 m. 11m covered by A=9 m covered by B Headstart in 11m race=2m Headstart in 10000m race=(2*10000)/11=1818m

In the solution, it is said B must be in middle of the 5th round. How did we reach to this conclusion?

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please Akhilesh Singh SIR reply to my question asked in the previous question and also if the ans is wrong in my booklet then also please let me know please sir please

find the value of 72540/5 + 72540/25 +78540/125 & the ans is given on my book is 17967.6 how to solve Akhilesh Singh sir please help me to solve this the process that U have said once is not matching with the ans in my booklet