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Answer
@Vemula Gopal
Suppose A as 1 square (also written as 1^2 which is equal to 1)
B as 2 square (2^2 equals 4)
C as 3 square (3^2 equals 9)
A+B+C= 1^2 + 2^2 + 3^2 = 1+4+9 = 14
for BCD, we already know the values of B and C
the next number that comes in this order is 4 square (let's take it as D)
B+C+D= 2^2 + 3^2 + 4^2 = 4+9+16 = 29
Hence, ABC:14 :: BCD:29
