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Question
A tank has capacity of 10 gallons and is full of alcohol. 2 gallons of alcohol are drawn out and the tank is again filled with water . this process is repeated 5 times .find out how much alcohol is left in the resulting mixture finally?
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Answer
Total capacity = 10 gallons.
Two gallons are being replaced every time.
Alcohol left after repeating the process 5 times = 10* (1-2/10)^5 = 10 * (4/5)^5 = 10 * 0.32768 = 3.2768 Gallons
