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Question
A man has 100 kg of grains of 2 types, A and B, in a ratio of 2:3. Grain A sells for Rs.10 less per kg than Grain B. Sita and Gita each purchase some amount of Grain A and B, and at the end, Sita pays Rs 200 more than Gita. If it is known that no grain is left with the man, and Gita buys 20kg of grain B, how many kg of grain A did Sita buy?
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Answer
let the amount of grain A sita buy be A and CP of grain a be x and grain B be x+10
total amount paid by sita = 40(x+10) + A(x)
total amount gite paid = 20(x+10) + (40-A)(X) + 200
equating the above two equations , A=10
