A man has 100 kg of grains of 2 types, A and B, in a ratio of 2:3. Grain A sells for Rs.10 less per kg than Grain B. Sita and Gita each purchase some amount of Grain A and B, and at the end, Sita pays Rs 200 more than Gita. If it is known that no grain is left with the man, and Gita buys 20kg of grain B, how many kg of grain A did Sita buy?

see there are like s- 40(x+10) then g- 20(x+10) diff abhi hai 20x+200 ka mujhe chaiye only 200 so i will give 20 x to to geeta and then 10x and 10x to both so seeta will have 10 quantity

let the amount of grain A sita buy be A and CP of grain a be x and grain B be x+10
total amount paid by sita = 40(x+10) + A(x)
total amount gite paid = 20(x+10) + (40-A)(X) + 200

equating the above two equations , A=10