A cuboid is inscribed in a sphere. The diameter of the sphere is 50. The total surface area of the cuboid is 4896. The sum of all edges of the cuboid is..... a)368 b)344✔ c)336 d)380 How do I slove this sum?

Diameter of Sphere is 50. (Diagonal of cuboid = Diameter of the sphere) Diagonal of cubiod, sq.rt(l^2 + h^2 + b^2) = 50,

Also total surface area 2(lh+lb+bh) = 4896

we know (l+b+h)^2 = l^2 + b^2 + h^2 + 2lb + 2bh+ 2hl

just substitute the values, you will get l+b+h = 86

Sum of edges = 4(l+b+h) = 4*86 = 344.

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