A can do a piece of work in 10 days while B can do it in 15 days. They begin together but 5 days before the completion of the work , B leaves off. find the total number of days for the work to be completed?

Hi Vamsi,

Let the work to be completed be 30 units. So A does 3 units of work in a day and B does 2 units of work in a day. They work together for x days, so they will finish (3+2)*x =5x units of work. Now only 30-5x units of work is left and A finishes it in 5 days . So 30 - 5x = 15 => x = 3
So they work together for 3 days and then A works alone for 5 days. Hence total number of days = 3+5 =8

Let the work to be completed be 30 units. So A does 3 units of work in a day and B does 2 units of work in a day. They work together for x days, so they will finish (3+2)*x =5x units of work. Now only 30-5x units of work is left and A finishes it in 5 days . So 30 - 5x = 15 => x = 3
So they work together for 3 days and then A works alone for 5 days. Hence total number of days = 3+5 =8