A 3 digit number is 11 times the 2-digit no formed by using the hundreds & the units digit of the 3-digit no respectively in the tens and & units place of the 2digit no. if the difference between digit in tens place & digit in hundreds place is 1, what is the digit in units place??

Let the number be xyz
(100x + 10y + z) = 11*(10x + z)
=> 100x + 10y + z = 110x + 11z
=> 10x = 10y - 10z
Also, y - x = 1 => y = x + 1
=> 10x = 10x + 10 - 10z
=> z = 1
So, the digit in the units place is 1

we can write equations as 100x+10y+z=11(10x+z) and y-x=1.. on solving the two equations we get z=1.. and three digit number is 231 which is equal to 11(21)...