3^√x+4^√x=5^√x Kindly, Solve this by process.

Question

Answer 1

The most simple method is to see the options, let's say, an option is available saying x=4. Try substituting this in the above equation, 3^(x^0.5)+4^(x^0.5)=5^(x^0.5)
3^(4^0.5)+4^(4^0.5)= 3^2+4^2=9+16=25
5^(4^0.5)=5^2=25
Therefore, LHS=RHS

Answer 2

The most simple method is to see the options, let's say, an option is available saying x=4. Try substituting this in the above equation, 3^(x^0.5)+4^(x^0.5)=5^(x^0.5)
3^(4^0.5)+4^(4^0.5)= 3^2+4^2=9+16=25
5^(4^0.5)=5^2=25
Therefore, LHS=RHS

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3^√x+4^√x=5^√x Kindly, Solve this by process.