3 boxes contains 10 fruits each.If the number of mangoes in the 3 boxes is 4,5,6 respectively.find the probability that a fruit picked at random from one of the boxes is mango?

Question

Answer 1

P = P(first box is selected)*P(mango is selected from the first box) + P(second box is selected)*P(mango is selected from the second box) + P(third box is selected)*P(mango is selected from the third box)

= 1/3 * 4/10 + 1/3 * 5/10 + 1/3 * 6/10
= 15/30 = 1/2

Answer 2

P = P(first box is selected)*P(mango is selected from the first box) + P(second box is selected)*P(mango is selected from the second box) + P(third box is selected)*P(mango is selected from the third box)

= 1/3 * 4/10 + 1/3 * 5/10 + 1/3 * 6/10
= 15/30 = 1/2

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3 boxes contains 10 fruits each.If the number of mangoes in the 3 boxes is 4,5,6 respectively.find the probability that a fruit picked at random from one of the boxes is mango?