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1Â year, 7Â months ago
2 men can do a piece of work in 6 days. If one finishes the work by himself in 16 days less than the other one, in how much time does the slower one finish the work?
1Â year, 7Â months ago
one person takes x days , slower one takes x+16 days and it is given together they take 6 days so adding one day work of both of them and equating to one day work of working them together,
1/x + 1/x+16= 1/6
=> x= 8, so answer is x+16 = 8+16 = 24 days answer.
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