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1 year, 4 months ago
1 year, 4 months ago
the answer is 81
this is how i got
let A=number of studs who passed in 1 subject
B= No of Studs in 2 subjects
C= No of studs in 3 subj
D= No of Studs in 4 subjects
Now A+B+C+D = 120 (total no of students)
A+2B+3C+4D= 95+92+91+88 = 366
Subtracting eqn2 from eqn1
B+2C+3D=246
Since B and C are atleast 1
So we get 3D=243
So D=81