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5 years, 3 months ago
`109.53. In AABC the perpendiculars drawn from A Band C meet the opposite sides at D E and F respectively AD BE and CF intersect at pointP. If _EPD = 116° and the bisectors of ZA andLB meet at Q then the measure of ZAQB is :AABC में A B और C से लंबवत खोंची गई रेखाएं विपरीतभुजाओं पर क्रमश: D E और F पर मिलती है। AD BE और CFबिंदु P पर परस्पर काटती हैं। यदि ZEPD = 116° है और ZAऔर B के द्विभाजक Qपर मिलते हैं तो ZAQB की माप कितनीहोगी?(A)96°(B) 122°(C) 124°(D) 64°-04. The perimeter of two similar triangles ABC`
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