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4 years, 5 months ago
9 months, 3 weeks ago
from the qn
eq 1 is 2p+5e+7s=30
eq 2 is 3p-6e+5s=15
eq 3 is 39e+S=6p+?
so here we have to multiply the first 2 equations with such a number that we get 3rd equation so multiply 1st eq with 3 and 2nd eq with 4 and subtract both the resultant equations to arrive at -6p+39e+s=30 so 39e+s=6p+30
so the answer is 30
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