XAT 2018 Question Paper

Team A has won both its matches and scored 5 goals while conceding 1. Thus, the possible scorelines for team A are (4-1) & (1-0), (3-1) & (2-0), (2-1) & (3-0).

Similarly, the possible outcomes for others teams are as follows:

B: (5-1) & (0-0) and (4-0) & (1-1)

C: (2-0) & (0-0) and (1-0) & (1-1)

D: (0-0) & (1-1)

E: (0-2) & (1-2) and (0-1) & (1-3)

F: (0-1) & (0-6), (0-2) & (0-5) and so on.

By carefully observing the above scorelines, the following table can be obtained.

From the above table, we can see that options B, C and D are possible and option A is not.

Hence, option A is the answer.

Let the required percentage be P.

Option A: P_A = (6.5 - 4) * 100/ 4 = 62.5%

Option B: P_B = (8 - 5) * 100/ 5 = 60%

Option C: P_C = (7 - 4) * 100/ 4 = 75%

Option D: P_D = (9 - 5.5) * 100/ 5.5 = 63.63%

Thus, option C shows the maximum year-on-year growth and is the answer.

Prof. Arithmetic: There are two such instances, during 2013-14 and 2015-16

Prof. Algebra: There are three such instances, during 2011-12, 2014-15 and 2015-16

Prof. Geometry: There are two such instances, during 2010-11 and 2013-14

Prof. Calculus: There are two such instances, during 2010-11 and 2014-15

Thus, there are 2+3+2+2 = 9 such instances.

Hence, option C is the answer.

Research efficiency = (total number of publications)/(total time spent in research)

Prof. Arithmetic: RE = (8) / [90*(0.7 + 0.5 + 0.6)] = 8 / (18 * 9)

Prof. Algebra: RE = (8) / [90*(0.3 + 0.4 + 0.25)] = 8 / (9.5 * 9)

Prof. Geometry: RE = (8) / [90*(0.75 + 0.25 + 2)] = 8 / (12 * 9)

Prof. Calculus: RE = (8) / [90*(0.55 + 0.55 + 0.4)] = 8 / (15 * 9)

Thus, we can observe that Prof. Arithmetic has the lowest efficiency.

Hence, option A is the answer.

Showrooming is the process in which an individual visits a showroom to know how a product looks and feels before buying it online at a discount. Therefore, option B is the right answer.