[Download PDF] TS ICET 2014 Question Paper Paper with Solutions

Instructions

For the following questions answer them individually

Question 121

A pole subtends angles $$30^\circ, 45^\circ, 60^\circ$$ respectively at points A, B and C all lying on a horizontal line through the foot of the pole. Then $$\frac{AB}{BC} =$$

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Question 122

$$x^4 - 4x^3 + 6x^2 - 4x + 1 = 0(x \neq 0)$$
$$\Rightarrow x + \frac{1}{x} =$$

Video Solution

Question 123

If x - 7 is a factor of the polynomial f(x), then a factor of $$f(2x^2 - 1)$$ among the following is

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Question 124

The remainder obtained when $$1! + 2! + 3! + ...... + (2014)$$ is divided by 7 is

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Question 125

$$\sqrt{(x + 1)(x + 2)(x + 3)(x + 4) + 1} =$$

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Question 126

The sum of seven consecutive even integers is s. Then, in terms of s, the greatest of these integers is

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Question 127

The maximum value of the expression $$2 + 8x - x^2$$ is

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Question 128

$$\frac{b}{a} = \frac{c}{b} = \frac{d}{c} \Rightarrow (a - c)^2 + (c - b)^2 + (b - d)^2 - (d - a)^2 =$$

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Question 129

The sum of first fifty odd natural numbers is

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Question 130

The coefficient of $$x^3$$ in the expansion of $$\left(x^2 - \frac{1}{x^3}\right)^9$$ is

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CAT Content

TS ICET 2014 Question Paper

TS ICET 2014 Question Paper

A pole subtends angles $$30^\circ, 45^\circ, 60^\circ$$ respectively at points A, B and C all lying on a horizontal line through the foot of the pole. Then $$\frac{AB}{BC} =$$

$$x^4 - 4x^3 + 6x^2 - 4x + 1 = 0(x \neq 0)$$$$\Rightarrow x + \frac{1}{x} =$$

If x - 7 is a factor of the polynomial f(x), then a factor of $$f(2x^2 - 1)$$ among the following is

The remainder obtained when $$1! + 2! + 3! + ...... + (2014)$$ is divided by 7 is

$$\sqrt{(x + 1)(x + 2)(x + 3)(x + 4) + 1} =$$

The sum of seven consecutive even integers is s. Then, in terms of s, the greatest of these integers is

The maximum value of the expression $$2 + 8x - x^2$$ is

$$\frac{b}{a} = \frac{c}{b} = \frac{d}{c} \Rightarrow (a - c)^2 + (c - b)^2 + (b - d)^2 - (d - a)^2 =$$

The sum of first fifty odd natural numbers is

The coefficient of $$x^3$$ in the expansion of $$\left(x^2 - \frac{1}{x^3}\right)^9$$ is

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$$x^4 - 4x^3 + 6x^2 - 4x + 1 = 0(x \neq 0)$$
$$\Rightarrow x + \frac{1}{x} =$$