Suppose f(x) = (x - 2)(x - 5)(x - 7).
If a number $$\alpha$$ is chosen from {1, 3, 4, 5, 6, 7, 8, 9, 10} randomly, the probability that it satisfies the equation $$f(\alpha) = 0$$, is

A

$$\frac{1}{3}$$

B

$$\frac{2}{5}$$

C

$$\frac{3}{7}$$

D

$$\frac{2}{9}$$