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The descending order of $$\sqrt[4]{10}, \sqrt[3]{6}, \sqrt{3}$$ is
$$\sqrt[4]{10}, \sqrt{3}, \sqrt[3]{6}$$
$$\sqrt[4]{10}, \sqrt[3]{6}, \sqrt{3}$$
$$\sqrt{3}, \sqrt[3]{6}, \sqrt[4]{10}$$
$$\sqrt[3]{6}, \sqrt[4]{10}, \sqrt{3}$$
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