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A pole subtends angles $$30^\circ, 45^\circ, 60^\circ$$ respectively at points A, B and C all lying on a horizontal line through the foot of the pole. Then $$\frac{AB}{BC} =$$
$$\frac{1}{\sqrt{3}}$$
$$\sqrt{3} + 1$$
$$\sqrt{3}$$
$$\sqrt{3} - 1$$
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