A pole subtends angles $$30^\circ, 45^\circ, 60^\circ$$ respectively at points A, B and C all lying on a horizontal line through the foot of the pole. Then $$\frac{AB}{BC} =$$

A

$$\frac{1}{\sqrt{3}}$$

B

$$\sqrt{3} + 1$$

C

$$\sqrt{3}$$

D

$$\sqrt{3} - 1$$