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The coefficient of middle term in the expansion of $$(1 + x)^{40}$$ is
$$\frac{1.3.5 .... 39}{20!} 2^{20}$$
$$\frac{1.3.5 .... 39}{20!}$$
$$\frac{21.22 .... 40}{20!}$$
$$40! 2^{20}$$
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