SNAP 2018 Question Paper

Marathi, English and Tamil books can be arranged in 3! ways.

All the Marathi books can be arranged among themselves in 5! ways.

Similarly, the English and Tamil books can be arranged among themselves in 3! ways.

The total number of ways in which the books can be arranged = 3!*5!*3!*3!

=25920

A is the correct answer.

Due to stoppages, the bus will cover 10 km less.

Time taken to cover 10 km = $$\ \frac{10}{50}\times\ 60\ \min$$

=12 min

A is the correct answer.

It is given that A can do a piece of work in 10 days and B can do the same work in 15 days.

Let the total work be LCM of (10, 15) = 30 units

Amount of work done by A in one day = $$\ \frac{\ 30}{10}$$ = 3 units

Amount of work done by B in one day = $$\ \frac{\ 30}{15}$$ = 2 units

Amount of work done by A and B together in one day = 3+2=5 units

So, together will complete 5*4 units i.e 20 of work in four days.

The amount of work left out = 30-20=10 units

The fraction of work left out = $$\ \frac{\ 10}{30}$$ = $$\ \frac{\ 1}{3}$$

D is the correct answer.

It is given 20% of x = y

x=5y

We have to find y% of 20 = $$\ \frac{\ y}{100}\times\ 20$$  

=$$\ \frac{\ y}{5}$$

=$$\ \frac{\ x}{25}$$

= 4% of x

Let Anu finishes the race in t hours.

Speed of Anu = $$\ \frac{\ 4000}{t}$$ m/hour

Speed of Bhanu = $$\ \frac{\ \left(4000-600\right)}{t}$$ m/hour Since Anu wins the race by 600m

Time taken by Bhanu to finish the race = Time taken by Caira to cover 3800m.

Time taken by Bhanu = $$\ \frac{\ 4000}{\ \frac{\ 3400}{t}}\ =\ \ \frac{\ 20}{17}t$$

Speed of Caira = $$\ \frac{\ 3800}{\ \frac{\ 20}{17t}}\ =\ \ \frac{\ 3230}{t}$$ m.hr.

To finish the race at the same time Anu should give Caira a headstart of 4000-3230 = 770m

C is the correct answer.

Surface area of one bigger box =2(25×20+20×5+5×25)
=1450cm2
By adding 5% for overlaps =1450+72.5=1522.5cm2
Area for 250 bigger boxes =1522.5×250cm2
Cost for 250 bigger boxes =1522.5×250×4=Rs.152250
Surface area of smaller box =2(15×12+12×5+5×15)=630cm2
By adding 5% for overlaps =630+31.5=661.5cm2
Area for 250 small boxes =661.5×250×4=Rs.66150
Total cost =152250+66150=Rs.218400

$$\frac{(4)^2 \times 2^{n + 1} - 4 \times 2^n}{(4)^2 \times 2^{n + 2} - 2 \times 2^{n + 2}}$$

$$\frac{(2)^4 \times 2^{n + 1} - 2^2 \times 2^n}{(2)^4 \times 2^{n + 2} - 2 \times 2^{n + 2}}$$

$$\frac{(2)^3 \times 2^{n}*2 -2 \times 2^n}{(2)^3 \times 2^{n}*2^2 - 2^{n}*2^2}$$

$$\ \frac{\ 2^3\times\ 2-2}{2^3\cdot2^2-2^2}$$

$$\ \frac{\ 14}{28}$$

=0.5

We have :

Now h^2 +x^2 =625
and h^2 +(17-x)^2 =676
subtracting the equations we get 
34x=289+625-676
we get 34x =238
we get x=7
Therefore 
we get h =24
Therefore area = 1/2 (137)(24)
= 1644

($$p^3+3p^2q+3pq^2+q^3$$) - ($$p^3-3p^2q+3pq^2-q^3$$) - ($$6q(p^2 - q^2)$$)

=$$6p^2q+2q^3-6q(p^2-q^2)$$

= 8$$q^3$$ 

=8 (Since q = 1)

8 is the correct answer.

In Roman numerals,

The values of M = 1000, D = 500, C = 100, L=50, X = 10, V = 5, 1 = 1.

The value of MMXVIII = 1000+1000+10+5+1+1+1 = 2018

2018 is the correct answer.