# SNAP Profit and Loss Questions PDF [Most Expected]

The Profit and Loss is an important topic in the Quant section of the SNAP Exam. You can also download this Free Profit and Loss Questions for SNAP PDF with detailed answers by Cracku. These questions will help you practice and solve the Profit and Loss questions in the SNAP exam. Utilize this **PDF practice set, **which is one of the best sources for practicing.

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**Question 1:Â **An article when sold for 960 fetches 20% profit.What would be the percent profit /loss if such 5 article are sold for Rs. 825/-each?

a)Â 3.125 % profit

b)Â 3.125 % loss

c)Â Neither profit nor loss

d)Â 16.5 % profit

e)Â None of these

**1)Â AnswerÂ (A)**

**Solution:**

Let cost price of an article = $Rs.$ $100x$

If Selling price = Rs 960

=> Profit % = $\frac{960-100x}{100x} \times 100=20$

=> $960-100x=20x$

=> $20x+100x=120x=960$

=> $x=\frac{960}{120}=8$

Thus, cost price of 1 article = $100 \times 8 = Rs.$ $800$

If selling price = Rs. 825

$\therefore$Â **Profit %** = $\frac{825-800}{800} \times 100$

= $\frac{25}{8} = 3.125\%$

=> Ans – (A)

**Question 2:Â **The owner of an electronics shop charges his customers 22% more than the cost price .If the customer paid Rs 10,980 for DVD player then the what was the cost price of that DVD?

a)Â 8000

b)Â 8800

c)Â 9500

d)Â 9200

e)Â none of these

**2)Â AnswerÂ (E)**

**Solution:**

Let cost price = $Rs. 100x$

Selling price = Rs. 10,980

=>Â Profit % = $\frac{10980 – 100x}{100x} \times 100 = 22$

=> $10980-100x=22x$

=> $22x+100x=122x=10980$

=> $x=\frac{10980}{122} = 90$

$\therefore$ Cost price = $100 \times 90 = Rs. 9000$

=> Ans – (E)

**Question 3:Â **An item was bought at Rs. X and sold at Rs. Y, there by earning a profit of 20%. Had the value of X been 15% less and the value of Y been Rs. 76 less, a profit of 30% would have been earned. What was the value of â€˜Xâ€™

a)Â Rs. 640

b)Â Rs.400

c)Â Rs.600

d)Â Rs.800

e)Â Rs.840

**3)Â AnswerÂ (D)**

**Solution:**

C.P. = $Rs. x$

S.P. = $Rs. y$

Profit % = $\frac{y – x}{x} \times 100 = 20$

=> $\frac{y – x}{x} = \frac{20}{100} = \frac{1}{5}$

=> $5y – 5x = x$ => $6x = 5y$

=> $y = \frac{6 x}{5}$ ———–(i)

If,Â value of X been 15% less and the value of Y been Rs. 76 less

=> $x’ = \frac{85}{100} \times x = \frac{17 x}{20}$

=> $y’ = y – 76$

Profit % = $\frac{y’ – x’}{x’} \times 100 = 30$

=> $\frac{(y – 76) – (\frac{17 x}{20})}{\frac{17 x}{20}} = \frac{30}{100} = \frac{3}{10}$

=> $10 \times [(y – 76) – (\frac{17 x}{20}] = 3 \times \frac{17 x}{20}$

=> $10y – 760 – \frac{170 x}{20} = \frac{51 x}{20}$

=> $10y – \frac{221 x}{20} = 760$

Using, equaiton (i), we get :

=> $(10 \times \frac{6 x}{5}) – \frac{221 x}{20} = 760$

=> $12x – \frac{221 x}{20} = 760$

=> $\frac{19 x}{20} = 760$

=> $x = 760 \times \frac{20}{19}$

=> $x = 40 \times 20 = Rs. 800$

**Question 4:Â **Shri Ramlal purchased a TV set for Rs. 12,500 and spent Rs. 300 on transportation and Rs. 800 on installation. At what price should he sell it so as to earn an overall profit of 15% ?

a)Â Rs. 14,560

b)Â Rs. 14,375

c)Â Rs. 15,460

d)Â Rs. 15,375

e)Â None of these

**4)Â AnswerÂ (E)**

**Solution:**

Cost price of TV = Rs. 12,500

Amount spent on transportation = Rs. 300 and installation = Rs. 800

Net spent = Rs. (12500 + 300 + 800) = Rs. 13,600

Let selling price = $Rs.x$

Profit % = $\frac{x-13600}{13600} \times 100=15$

=> $x-13600=15 \times 136$

=> $x=2040+13600$

=> $x=Rs.$ $15,640$

=> Ans – (E)

**Question 5:Â **A trader sells an item to a retailer at 20% discount, but charges 10% on the discounted price, for delivery and packaging. The retailer sells it for Rs. 2046 more, thereby earning a profit of 25%. At what price had the trader marked the item?

a)Â Rs. 9400

b)Â Rs. 9000

c)Â Rs. 8000

d)Â Rs. 12000

e)Â Rs. 9300

**5)Â AnswerÂ (E)**

**Solution:**

Let Marked price of item = $Rs. 100x$

=> Selling price of trader = Cost price of retailer = $100x \times \frac{80}{100} \times \frac{110}{100}$

= $Rs. 88x$

Selling price of retailer = $Rs. (88x + 2046)$

Profit % = $\frac{(88x + 2046) – 88x}{88x} \times 100 = 25$

=> $\frac{2046}{88x} = \frac{25}{100} = \frac{1}{4}$

=> $x = \frac{2046 \times 4}{88} = 93$

$\therefore$ Marked price = $100 \times 93 = Rs. 9,300$

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**Question 6:Â **A starts a business with Rs. 2500. After one month from the start of the business, B joined with Rs. 4500 and A withdrew completely after eleven months from the start of the business. If the difference between Aâ€™s and Bâ€™s respective shares in the annual profit was Rs. 4800, what was the annual profit earned?

a)Â Rs. 14800

b)Â Rs. 16800

c)Â Rs. 14400

d)Â Rs. 11400

e)Â Rs. 15600

**6)Â AnswerÂ (B)**

**Solution:**

Amount invested by A = Rs. 2500 and by B = Rs. 4500

Both invested for 11 months.

Ratio of profit shared by A and B

= $(2500 \times 11) : (4500 \times 11)$

= $5 : 9$

Let total profit earned by A and B respectively = $Rs. 5x$ and $Rs. 9x$

=> $9x – 5x = 4800$

=> $x = \frac{4800}{4} = 1200$

$\therefore$ Total profit = $9x + 5x = 14x$

= $14 \times 1200 = Rs. 16,800$

**Question 7:Â **17 articles were bought for Rs. 3,910 and sold for Rs. 4,590. How much was the approximate profit percentage per article ?

a)Â 17%

b)Â 12%

c)Â 9%

d)Â 21%

e)Â 25%

**7)Â AnswerÂ (A)**

**Solution:**

Cost price of 1 article = Rs. $\frac{3910}{17}$ = Rs. 230

Selling price of 1 article = Rs. $\frac{4590}{17}$ = Rs. 270

Profit % = $\frac{270 – 230}{230} * 100$

= 17.39% $\approx$ 17%

**Question 8:Â **The cost price of an article is Rs. 390. If it is to be sold at a profit of 3.12 per cent, how much would be its approximate selling price ?

a)Â Rs. 410

b)Â Rs. 402

c)Â Rs. 417

d)Â Rs. 420

e)Â Rs. 442

**8)Â AnswerÂ (B)**

**Solution:**

Profit obtained in selling the article at 3.12%

= $\frac{3.12}{100} * 390 \approx$ Rs. 12

=> Selling price = 390 + 12 = Rs. 402

**Question 9:Â **The cost price of an article is Rs.1700. If it was sold at a price of Rs.2006, what was the percentage profit on the transaction?

a)Â 18

b)Â 12

c)Â 10

d)Â 15

e)Â 20

**9)Â AnswerÂ (A)**

**Solution:**

Profit = S.P. – C.P. = 2006 – 1700

= Rs. 306

=> Profit % = $\frac{306}{1700} * 100$

= 18%

**Question 10:Â **21 articles were bought for 6531 and sold for Rs.9954. How much was the approximate profit percentage per article?

a)Â 56%

b)Â 43%

c)Â 52%

d)Â 49%

e)Â 61%

**10)Â AnswerÂ (C)**

**Solution:**

C.P. of 1 article = $\frac{6531}{21}$ = Rs. 311

S.P. of 1 article = $\frac{9954}{21}$ = Rs. 474

=> Profit on 1 article = S.P. – C.P. = 474 – 311

= Rs. 163

$\therefore$ Profit % = $\frac{163}{311} * 100$

= 52.4% $\approx$ 52%