Question 33
In September 2009, the sales of a product were (2/3)rd of that in July 2009. In November 2009, the sales of the product were higher by 5% as compared to September 2009. How much is the percentage of increase in sales in November 2009 with respect to the base figure in July 2009?
Solution
Let the total sales in July 2009 be Rs. x
Then, sales in September 2009 = Rs. 2x/3
Sales in November 2009 :
= 105% of Rs.$$\ \frac{\ 2x}{3}$$
= Rs. $$\ \ \frac{\ 105}{100}\ \times\ \ \ \frac{\ 2x}{3}$$
= Rs. $$\ \frac{\ 7x}{10}$$
Now, the percentage change in sales :
$$\frac{\left(\frac{\ 7x}{10}-x\ \right)\ }{x}\times\ 100=\ \frac{\ -3x\ \ }{10x}\times\ 100\ =-30\%$$
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