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By what per cent was the total investment in the two districts more in 1996 as compared to 1995?
Total investment in 1996 = 3489.5 + 8352 = 11841.5
Total investment in 1995 = 7081.6 + 2923.1 = 10004.7
change = 1836.8
%change = $$\frac{1836.8}{10004.7} \times 100 $$
As we can see with apprximation method that above value will be less than 20 and more than 18
Hence most appropriate answer will be D) = 18
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