SSC CGL 7th March 2020 Shift-2

Instructions

For the following questions answer them individually

SSC CGL 7th March 2020 Shift-2 - Question 51


If 18 men can cut a field in 35 days, then in how many days can 21 men cut the samefield?

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SSC CGL 7th March 2020 Shift-2 - Question 52


The perimeter of an isosceles triangle is 50 cm.If the base is 18 cm, then find the length of the equal sides.

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SSC CGL 7th March 2020 Shift-2 - Question 53


A man buys two watches ‘A’ and ‘B’ at a total cost of ₹800. He sells both watches at the same selling price, and earns a profit of 18% on watch ‘A’ andincurs a loss of 22% on watch ‘B’. Whatare the cost prices of the two watches? (two place after decimal).

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SSC CGL 7th March 2020 Shift-2 - Question 54


The cost price of goods, for a shopkeeper, was X. He marked them at 15% above the cost price. Finally, he sold the goods at a discount of 25%. What is his profit/loss percentage ?

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SSC CGL 7th March 2020 Shift-2 - Question 55


The following table shows the age-wise brand ownership of mobile phone handsets.

If a total of 5000 ‘C’ mobile phone sets are sold till date, then how many are more than one year old?

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SSC CGL 7th March 2020 Shift-2 - Question 56


The following table shows the number of employees working in various departments of an organisation from 2016 to 2019.

In which year were the maximum number of employees working in the organization?

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SSC CGL 7th March 2020 Shift-2 - Question 57


AB is a diameter of a circle with centre O. The tangentat a point C on the circle meets AB producedat Q. If $$\angle CAB = 42^\circ$$, then what is the measure of $$\angle CBA$$?

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SSC CGL 7th March 2020 Shift-2 - Question 58


If radius of a circle is decreased by 11%, then the total decrease in the area of the circle is given as:

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SSC CGL 7th March 2020 Shift-2 - Question 59


If the perimeter of a certain rectangle is 50 units and its area is 150 sq. units, then how many units is the length of its shorter side?

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SSC CGL 7th March 2020 Shift-2 - Question 60


The value of $$1\frac{1}{8} \div \left(4\frac{1}{4} \div \frac{3}{5} of 8\frac{1}{2}\right) - \frac{2}{5} \times 1\frac{1}{3} \div \frac{4}{5} of 1\frac{2}{3} + \frac{11}{20}$$ is:

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