Question 53

A man buys two watches ‘A’ and ‘B’ at a total cost of ₹800. He sells both watches at the same selling price, and earns a profit of 18% on watch ‘A’ andincurs a loss of 22% on watch ‘B’. Whatare the cost prices of the two watches? (two place after decimal).

Solution

Let the selling price be x.

Total cost price = cost price for A + cost price for B

800 = $$\frac{x}{100 + 18} \times 100 + \frac{x}{100 - 22} \times $$100

8 = $$\frac{x}{118} + \frac{x}{78}$$

78x + 118x = 8 $$\times 78 \times 118

x = 73632/196 = 375.67

Cost price for A = $$\frac{375.67}{118} \times 100$$ = Rs.318.37

Cost price for B = 800 - 318.37 = Rs.481.63

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