Question 57

AB is a diameter of a circle with centre O. The tangentat a point C on the circle meets AB producedat Q. If $$\angle CAB = 42^\circ$$, then what is the measure of $$\angle CBA$$?

Solution

$$\angle C = 90\degree$$

$$\triangle$$ ABC,

$$\angle CAB + \angle C + \angle CBA = 180\degree$$

$$\angle CBA = 180 - 90 - 42 = 48\degree$$

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