AB is a diameter of a circle with centre O. The tangentat a point C on the circle meets AB producedat Q. If $$\angle CAB = 42^\circ$$, then what is the measure of $$\angle CBA$$?
$$\angle C = 90\degree$$
$$\triangle$$ ABC,
$$\angle CAB +Â \angle C +Â \angle CBA = 180\degree$$
$$\angle CBA = 180 - 90 - 42 = 48\degree$$
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