SNAP 2022 Question Paper

The area of the circle is 616.
So, the radius of the circle is $$\sqrt{\frac{616}{\pi}}=14$$
Hence, the length of the rectangle is 14*2=28 and the breadth equals 14
So, the area of the rectangle is 14*28=392 sq m

Let us assume that the radius of the circle is r cm and the side of the triangle ABE is a cm.

Then, side of triangle ABE,

$$\Rightarrow$$ $$r$$ = $$\frac{\triangle}{S}$$   (Where $$\triangle$$ = Area of triangle and S = semi-perimeter of triangle)

$$\Rightarrow$$ $$r = \frac{(\frac{\sqrt{3}}{4})\times a^2}{\frac{3a}{2}}$$ 

$$\Rightarrow$$ $$r = \frac{a}{2\sqrt{3}}$$ 

$$\Rightarrow$$ $$a = 2\sqrt{3}\times r$$ 

We are given that the area of square ABCD = 300 sq. cm.

$$\Rightarrow$$    $$a^2 = (2\sqrt{3}\times r)^2$$

$$\Rightarrow$$    $$300 = 12r^2$$

$$\Rightarrow$$    $$r = 5 cm$$

Hence, option C is the correct answer. 

Total number of students in Class 10th = $$\frac{30}{100}\times 2000$$ = 600

Out of these 600 students, the number of boys students in class 10th = $$\frac{80}{100}\times 600$$ = 480

The number of girls students in class 10th = $$\frac{20}{100}\times 600$$ = 120

In similar way we can calculate number of boys and girls in each class. Tabulating the same data 

From the table we can see that,

The number of boys studying in class 9th = 300

Sum of the number of the girls studying in class 10th and class 5th  = 120 + 90 = 210 

Hence, the required ratio = 300 : 210 = 10 : 7 

Therefore, option A is the correct answer. 

From the given table,
Revenue of A = 120 crores
Operating expenses = 70% of 120 = 84 crores
Profit = 120 - 84 = 36 crores

Similarly, calculating and tabulating the values for other companies,

Average profit of companies A and E = 48/2 = 24 crores

Downstream = boat + stream = $$\frac{12}{2}$$ + stream = 6 km/hr

Upstream =boat - stream = $$\frac{12}{4}$$ - stream = 3 km/hr

Solving the above equations we get boat = 4.5 km/hr and stream = 6 - 4.5 = 1.5

Speed of the stream = $$\frac{1}{3}$$rd of that of the boat in still river = 1.5

$$x_1 + x_2 = 4$$ and $$5x_1 - x_2 = 38$$. So, $$x_1 = 7$$ and $$x_2 =-3$$. Hence, c = 21

$$ \log _9 {(Y+6)^2} + \log _{27} {(11-Y)^3} = \log _3 {(Y+6)} + \log _3 {(11-Y)} = \log _3 {(66+5Y-Y^2)}$$
So, $$ 66+5Y-Y^2 = 3^4 = 81$$
Or, $$Y^2-5Y+15=0$$
This equation has no real roots

Total work in terms of girl days i.e only girls working is 16*5=80 GD
Total work in terms of Women days i.e only women working is 15*4=60 WD
Therefore 80 GD=60 WD
1 WD=4/3 GD
So total work in terms of given people is 10x GD+9x WD=80 GD
10x GD+ 12x GD=80 GD
22x=80
x=40/11 days

Let the ratio = m:n

Let CP of the mixture per kg = k

(1.2)k = SP = 42

k = 42/1.2 = 35/-

32(m)+38(n) = (35)(m+n)

32m+38n = 35m+35n

3m = 3n

m/n = 1

Hence the ratio is m:n = 1:1

So the answer is option C.

The amount paid by Veen and Priya = 2400 - Seema’s share = 2400 - 40% of 2400 = Rs 1440
Thus, the amount paid by Veena = 3/5 x 1440 = Rs 864