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Find the ratio in which a shopkeeper mixed two types of rice of cost 32/- per kg and 38/- per kg, if he sold the mixed rice for 42/- per kg at 20% profit ?
Let the ratio = m:n
Let CP of the mixture per kg = k
(1.2)k = SP = 42
k = 42/1.2 = 35/-
32(m)+38(n) = (35)(m+n)
32m+38n = 35m+35n
3m = 3n
m/n = 1
Hence the ratio is m:n = 1:1
So the answer is option C.
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