CAT 2001 Question Paper

Total number of man-hours spent onsite = 75+100+150 = 325
The sum of the estimated and actual effort for offshore design = 200 (approx)
The estimated man-hours of offshore coding = 425
The actual man-hours of offshore testing = 300 (approx)
Half of the man-hours of estimated offshore coding = 210(approx)
So, option c) is the closest

Total working hours = 1150
So, we have to find the task where the number of working hours is approximately 575
Coding = 425 + 100 = 525
Design = 100 + 75 = 175
Offshore testing = 300
Offshore testing + design = 300 + 100 = 400
So, option a) is the correct answer

Total number of hours needed for testing = 300+150 = 450
New number of hours spend offshore for testing = 300/2 = 150
So, required percentage = 150/450 * 100% = 33.33%
From the options, the closest answer is option b)
 

Total offshore work = 100+420+300 = 820. If 50% of the offshore work were to be carried out onsite i.e 410 carried out onsite. 

So new work carried out onsite is in design is [80 + (100*410)/(825)] which is around 130. Also new work carried out onsite is in coding is [100 + (425*410)(825)] which is around 315. 

And new work carried out onsite is in testing is [150+(300*410)(825)] which is around 300. Hence the amount of coding done is greater than that of testing. 

We know that quantity between Vaishali and jyotishmati is 300,

So quantity in avanti-vaishal route should be 700.

Now at jyotishmati the required quantity is 400+700 = 1100.

But through vaishali only 300 comes , so  800 should come through Vidisha-jyotishmati route.

Now demand at vidisha is 200. So total quantity required in avanti - vidisha route is 800+200=1000. Hence option D. 

We know that quantity between Vaishali and jyotishmati is 300,

So quantity in avanti-vaishal route should be 400+300=700.

So free capacity is 1000-700=300. Hence option D . 

We know that quantity between Vaishali and jyotishmati is 300, So quantity in avanti-vaishal route should be 700. Now at jyotishmati the required quantity is 400+700 = 1100.

But through vaishali only 300 comes , so  800 should come through Vidisha-jyotishmati route.

Now demand at vidisha is 200. So total quantity required in avanti - vidisha route is 800+200=1000.

Hence, free capacity available = 1000-1000=0. Hence option D. 

If suppose effort allocation is inter-changed between operations B and C, then C and D, and then D and E then operation E will have value of B . So arranging effort in E in ascending order we have company 4 ,company 5 , company 3, ... Hence company 3 is ranked third. Hence option B. 

Now from B through F total work done is 81.7%. Dividing it in 5 we get 16.34. So difference in operation E is 28.6-16.34 = 12.3 %. Hence there is a reduction of 12.3 .

Operations B, C and D have more effort weightage in companies 1,3,5,6.

Also we notice that among them operation E has highest already, and for E company 5 has already the highest percentage. So redistributing the share of E would increase further more. Hence option D.