TISSNET 2018

4 chocolates of type D cost Rs. 44 and 5 chocolates of type C cost Rs.40. So, Rs.84 is spent already. Now Rs.16 is left and cost per Chocolate of type A and B are multiples of 5. So to maximise the expenditure, 3 of type B and 0 of type A or 1 of type B and 1 of type A can be bought.

We can see 2 is in the odd places and 4 in the even places.

In the 1st 18 terms, there are 9 4's and 2's which sum up to 54 and the 19th term being 2 is added to get sum of 1st 19 terms as 56.

let x% of 1425 be 68.40.

So, (x/100)*1425 = 68.40

=> x = 6840/1425

=> x =  4.8%

When a number less than 1 but greater than zero is multiplied by itself, the product is less than the original number. Like 0.9x0.9 = 0.81 < 0.9

So, (0.99^5) > (0.99^6)

From the graph, we can see that the Indian and China economies have both experienced similar trends so statement one is true while the other two statements cannot be concluded from the graph so only first statement is true.

Let the 2 nos. be 7x and 9x. As their sum is 112,

we can write 7x + 9x = 112

=> x = 7

So the larger number is 9x7 = 63

From the graph, we can see clearly that the increase in the period from 1994-1997 is greater than the increase in the period in 1995-2000.

Let x be the number of candidates who appeared for the exam.

From the graph, we can infer that in 1998, 80% of the students passed the exam, which is given to be 21200.

So, $$80\ \%\ of\ x=\ 21200$$

=>$$\ \frac{\ 80}{100}\times\ x=\ 21200$$

=> $$\ \frac{\ 4}{5}\times\ x=\ 21200$$

=>$$\ \ x=\ \ \frac{\ 5}{4}\times\ 21200$$

.'. x=26500, Option C

Let the total number of men be x.

Given, the total percentage of literate people= 75%, which is given to be 1200.

So, $$75\%\ \times\ x=1200$$

=> $$\ \frac{\ 75}{100}\times\ x=1200$$

=> $$\ \frac{\ 3}{4}\times\ x=1200$$

=> $$\ \ x=1200\times\ \ \frac{\ 4}{3}$$

.'. x= 1600.

It is given that 35% of the men have attained secondary level education.

So, 35% of 1600= $$\ \frac{\ 35}{100}\times\ 1600$$= 560 is our answer.

Let the total number of men be x.

Given, the total percentage of literate people= 75%, which is given to be 1200.

So, $$75\%\ \times\ x=1200$$

=> $$\ \frac{\ 75}{100}\times\ x=1200$$

=> $$\ \frac{\ 3}{4}\times\ x=1200$$

=> $$\ \ x=1200\times\ \ \frac{\ 4}{3}$$

.'. x= 1600.

Since men:women ratio is 10:8, i.e for every 10 men, there are 8 women. 

So, for 1600 men, number of women will be $$\ \frac{\ 8}{10}\times\ 1600$$= 1280.

Women literacy is given to be 60%.

So, number of literate women= $$\ \frac{60}{100}\times\ 1280$$= 768- Option C.