TISSNET 2018

If the difference between any two dates is multiple of 7, then those two fall on same day of the week in any given month. Thus, 13 and 27 fall on same day.

=> Ans - (C)

Number of odd days between 15 Aug 1895 to 31 Dec 1895 = $$16+2+3+2+3=26$$

Number of odd days between 01 Jan 1896 and 31 Dec 1904 = $$2+1+1+1+1+1+1+1+2=11$$

Number of odd days between 01 Jan 1905 to 15 August 1905 = $$3+0+3+2+3+2+3+15=31$$

=> Total odd days = $$(26+11+31)\%7=5$$

So, the 15th August 1895 is a Thursday

Let total population of state R = $$100x$$ million

% of people below poverty line in state R = $$24x$$ and above poverty line = $$76x$$

Males above poverty line = $$\frac{2}{5}\times76x=1.9$$

=> $$x=\frac{0.5}{8}=0.0625$$

$$\therefore$$ Total population of state R = 6.25 million

=> Ans - (A)

For distribution- 2 we can see that the graph is concentrated on the left side and for distribution- 3 the graph is concentrated on the right side. So, mean of distribution- 2 is less than the mean of distribution- 3. Therefore, option D is false.

The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they coincide only once, i.e., at 12 o'clock). The hands overlap about every 65 minutes, not every 60 minutes. Thus the minute hand and the hour hand coincide 22 times in a day.

Thus, the hands of a clock overlap 22 times a day. Thus the hands of the clock overlap at 12:00, ~1:05, ~2:10, ~3:15, ~4:20, ~5:25, ~6:30, ~7:35, ~8:40, ~9:45, ~10:50. Note that there is no ~11:55. This becomes 12:00.

=> Ans - (B)

If $$\tan(A) = 0$$ and $$\sin(A) = 0$$

=> $$\angle A=0^\circ$$

$$\therefore$$ $$\cos(A)=cos(0^\circ)=1$$

=> Ans - (B)

% of salt in the solution = $$\frac{1}{(1+19)}\times100$$

= $$\frac{100}{20}=5\%$$

=> Ans - (B)

The pattern followed is that consecutive multiples of 8 are added.

4 + 8 = 12

12 + 16 = 28

28 + 24 = 52

52 + 32 = 84

=> Ans - (B)

The first series is a set of prime numbers, second and fourth are squares of prime numbers, hence third series is the odd one.

=> Ans - (C)

If we arrange the five numbers in ascending order, median is 10, and fifth number is 50, thus series : x, y, 10, z, 50

Also, mean is 20, => $$\frac{x+y+10+z+50}{5}=20$$

=> $$x+y+z=100-60=40$$

Now, mode is 10, Case 1 : If $$x=10$$, then we can have $$y=z=15$$, and thus 10 cannot be mode.

Case 2 : If $$x=y=10$$, thus $$z=20$$, and mode is 10

Thus, modal value appears 3 times.

=> Ans - (D)