SNAP Coding and Decoding Questions

In the code language, the first letter of the original word is replaced with its next letter in the English alphabet. The second letter is replaced with a letter that is two ahead of the original letter, in the English alphabet and so on. So, the code for ‘BANNER’ is ‘CCQRJX’. Option d) is the correct answer.

On comparing I and II, we can infer that "is" is the common word where "oi" is the code for it. Similarly, if we compare I and III and I and IV we get the codes for "happy" and "life" as "Im" and "st". 

On comparing IV with II and III, we can see that the common words are "match" and "to". The code which is common between them is "le" and "dk". Hence, the code for "match" is "le" and for "to" it is "dk". The remaining code "rc" is for Bottle and "ky" is for "forever".

The codes for the given words are as follows,

Happy - lm 

is - oi 

match - le 

to - dk 

life - st 

bottle - rc 

forever - ky

 risky/betting = pn/az 

key/be = kr/fc

The code for key/be is kr/fc. fc can be either ‘key” or “be”. Hence, option D is the correct answer.

The numerical position of E is 5, A is 1 and T is 20 - 5*1*20 = 100.
The numerical position of C is 3, A is 1 and T is 20 - 3*1*20 = 60.

BAIN = 2*1*9*14 = 252.
PAINT = 16*1*9*14*20 = 40320.
HIGH = 8*9*7*8 = 4032.
RAISE = 18*1*9*19*5 = 15390.
As we can see, PAINT will be coded as 40320. Therefore, option B is the right answer.

The coding is based on the following rule. The first word is replaced by the word preceding it, the second word is replaced by the word succeeding it, the third word is replaced by the word preceding it and so on. Only option c satisfies this condition.

MASTER is written as 79 7 115 121 31 109

In the alphabetical order M=13, A=1, S=19, T=20, E=5, R=18

The sequence is  (n x 6)+1: 79= 13x6+1  7= 1x6+1  115= 19x6+1

.....

Thus the sequence for LAUGH will be

L= 12x6+1 =73

A=1x6+1=7

U=21x6+1= 127

G=7x6+1= 43

H=8x6+1= 49

Answer: 7371274349

As per the CAB code, A is coded as 5 and should be the same in case of A in DAD.

For C in the CAB, C is the third letter in the English Alphabet. 

So, 1) $$3^2=9$$

2) $$9^3=\ 729$$

3) 729-6= 723.

These 3 steps are followed to find the code of C.

If we cross check with B, the second alphabet,

1) $$2^2=4$$

2) $$4^3=\ 64$$

3) 64-6= 58- Which is how B is coded.

So, for D- the fourth alphabet, we have

1) $$4^2=16$$

2) $$16^3=\ 4096$$

3) 4096-6= 4090.

So, Option B is the correct one.

MONEY is coded as 144 200 171 0 600
M = 144 = 13^2-25
O = 200 = 15^2-25
N =171 = 14^2-25
E =0      = 5^2-25
Y = 600  = 25^2-25
So similarly following for Dollar
we get
D= 16-25
O = 225-25
L =144-25
A =1-25
R = 324-25
We get DOLLAR as - 9 200 119 119 - 24 299

We have 
CAT 389376 DOG 
Now CAT = 3+1+20 =24 
24^2 =576 
DOG =4+15+7 =26
26^2 =676
Now (576)(676) = 389376
Now following the same pattern :
CAN = 3+1+14 =18
18^2 =324
Now 571536/324 = 1764 
Now $$\sqrt{\ 1764}\ =42$$
= GIFT (7+9+6+20)

In the first pair of words, vowels are taken together and written down in the alphabetical order followed by the consonants in the same alphabetical order.

So, for BEGUM, the vowels are E and U. The consonants are B,G and M. When arranged alphabetically, it becomes EUBGM- option A.

The pattern is as follows:

Previous alphabets of DRINK is CQHMJ respectively, now they have reversed the order, interchanged the first term with last, the second term with second last and so on.

So the term "DRINK" will be=JMHQC

Similarly, HONEY will be XDMNG.

Option C

NOR is coded as 2-3-6, then how should REST

M=1

N=2

O=3

P=4

..

..

REST=6-19-7-8

‘3a, 2b, 7c’ means ‘Truth is Eternal’

‘7c, 9a, 8b, 3a’ means ‘Enmity is not Eternal’

‘9a, 4d, 2b, 8b’ means ‘Truth does not perish’.

Eternal= 7c

is = 3a

not = 9a

'Enmity’ in that language 8b

Option C

The sum of the alphabetical order of CONSTABLE =91

STABLE= 19+20+1+2+12+5= 59

Option B

With close observations, we can see that each letter has a particular digit associated with it.

B-5

E-7

A-3

U-0

T-4

I-1

F-2

L-8

R-9.

.'. FUTURE will be coded as 204097, which is given in Option B.

A fruit grows on tree. But according to the code words, tree is referred to as Sky. So, as per this question, a fruit grows on sky.

Let us represent a square, circle, triangle and rhombus as s, c, t and r respectively and form eqns.

1) s*c=t

2) s=c*r

3) (t^2)=(r^3)

Expressing t and r in 3rd eqn in terms of s and c, we get:

=>((s*c)^2) = ((s/c)^3)

=> s = (c^5) which is shown in option A.

We see that in word PROMOTION

P---> Q

R--->S

O--->P 

MOTION --->89

Hence for DEMOTION the coding will be

D--->E

E--->F 

MOTION--->89

EF89 is the correct answer

B onwards all alternate alphabets are written in lower case. The alphabets will look like this

AbCdEfGhIjKlMnOpQrStUvWxYz

First month of second-half of year is July which will be written as jUlY

We see that the device takes the biggest number which is not in descending order and places it at its place.

Input : 09 25 16 30 32 18 17 06

Step I : 32 09 25 16 30 18 17 06

Step II : 32 30 09 25 16 18 17 06

Step III : 32 30 25 09 16 18 17 06

Hence Option D is correct

Since the device is sorting the number in descending order with biggest number and one at a time.

For Input 16 09 25 27 06 05

Step I : 27 16 09 25  06 05

Step II :  27 25 16 09 06 05

After which all the numbers are sorted. Hence 2 steps are needed

We see that the device takes the biggest number which is not in descending order and places it at its place.

For Input : 25 08 35 11 88 67 23

Step I : 88 25 08 35 11 67 23

Step II : 88 67 25 08 35 11 23

Step III : 88 67 35 25 08 11 23

Step IV : 88 67 35 25 23 08 11

Step V : 88 67 35 25 23 11 08

We see that in this, the number is sorted in the descending order in which every step the biggest number which is not in the correct place picked and placed at its place.

Input: 03 31 43 22 11 09

Step I = 43 03 31 22 11 09

Step II = 43 31 03 22 11 09

Step III = 43 31 22 03  11 09

Step IV = 43 31  22 11  03 09

Step V = 43 31 22 11 09 03

Total 5 steps are needed.

Since we know that in every step the series gets sorted in descending order. But it is not possible to know that from which position the number was picked.