SNAP 2024 Question Paper

It has been given that the coins are in the ratio of 3x: 4x: 5x.
Total value of all the coins combined = 3x*1 + 4x*2 + 5x*5 = 36x
It has been given that 36x = 1296
Hence, x = $$\frac{1296}{36}$$ = 36
Hence, the total number of Rs. 2 coins = 4 * 36 = 144 coins.
Therefore, option D is the right answer. 

Average speed=Total distance/Total time
Time=distance/speed
Let total distance=x
Time taken for one fourth distance=(x/4)/20=x/80
Time taken for half the distance=(x/2)/40=x/80
Time taken for the other one fourth=(x/4)/10=x/40
Total time=4x/80
=x/20
Average speed=(x)/(x/20)
=20 km/hr

Let the first term of the series be a and the common difference be d.
The 12th term is a+11d = 42. Sum of the first, second and 33rd terms = a+(a+d)+(a+32d) = 3a + 33d = 3(a+11d) = 3*42 = 126.
Product of the first, second and 33rd terms is a*(a+d)*(a+32d).
Since the sum is constant, the product is maximum when all the terms are equal. => a = a+d = a + 32d => d = 0.

Let the number of boys in the class= B

number of girls in the class = G.

"The number of games involving a girl and a boy is 150" ==> Bc1*Gc1 = 150 ==> B*G = 150 --- (1)

"the number of games involving two girls is 60 less than the number of games involving two boys" ==> Gc2 +60 =Bc2 ==> G(G-1) + 120 = B(B-1) --- (2)

By solving equations (1), (2) we can deduce the values of B, G.

B=15, G=10.

So the total strength of the class = 10+15 = 25.

The total number of balls in the bag = 15
Total number of ways of drawing out two balls = 15C2 = 105
Favorable ways = 6C1*9C1 = 54
Hence, the required probability is given by 54/105 = 18/35.

$$4$$ kg$$\rightarrow$$ Rs.$$120$$
then $$1$$kg $$\rightarrow$$ Rs.$$\Large\frac{120}{4}$$ $$=$$ Rs.$$30$$
Reduced price: $$30$$ $$\times$$ $$\Large\frac{20}{100}$$ $$=$$ Rs.$$6$$/kg
Original price: $$6$$ $$\times$$ $$\Large\frac{100}{(100-20)}$$ $$=$$ $$6$$ $$\times$$ $$\Large\frac{100}{80}$$ $$=$$ Rs.$$7.50$$/kg

Let the principal be Rs.P
Let the time period be x years
Then, After x years, P will become Rs.31P
⇒ Interest = 31P - P = Rs.30P
⇒ $$\dfrac{P \times 15 \times x}{100} = 30P$$
⇒ x = 200
Hence, After 200 years, the sum of money will become 31 times of itself.

Cost Price of 45 kg of rice $$= 20\times15+25\times20 = 300+500 = Rs.800$$
Selling Price of 45 kg of rice $$= 45\times24 = Rs.1080$$

Profit = 1080-800 = Rs.280
Profit percentage = $$\dfrac{280}{800}\times100 = 35$$

Number of chocolates with Ravi=(30/100)*350=105
Number of chocolates with Srujay=(10/100)*350=35
Difference between them=105-35=70 chocolates

Number of chocolates with Ravi=(30/100)*350=105
Number of chocolates with Srujay=(10/100)*350=35
Number of chocolates with Praful=(20/100)*350=70
Average of chocolates receive by these three=(105+35+70)/3
=70