Question 55

In a bag, there are 6 red balls, 3 green balls and 7 blue balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?

Solution

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Probability that the ball is neither red nor blue = Probability that the ball is green
Probability that the ball is green = (Number of green balls)/(Total number of balls) = 3/(6+3+7) = 3/16.

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