SNAP 2015 Question Paper

If the question would have been "can be" , then all the options would have been correct but since it has been given as 'is' , only option d satisfies.
Option A: The polynomial can start with any power of p. The order of powers of p does not make any difference. 
Option B:It is possible only when p = a or b or c ...... or z
Option C:The polynomial can start with any power of p. The order of powers of p does not make any difference.
Option D:This is true in all the cases.

Total number of humans = 9 => total legs = 9*2=18

Total number of lions = 9*9*9 => total legs= 9*9*9*4=2916

Total number of cubs = 9*9*9*9=> total legs =9*9*9*9*4=26244

So total legs= 29178

The above area can be obtained by the following operation: Area of Big Square - Area of the Bigger circle + $$4\times\ $$ Area of Smaller Circle + $$8\times\ $$ Overlapping Area of smaller circles

i) Area of Big Square = $$24\times\ 24=576$$

ii) Area of Big circle = $$\pi\ 12^2\ =\ 144\pi\ $$

iii) Area of smaller circle = $$\pi\ 6^2\ =\ 36\pi\ $$

iv) For Area of smaller common area = 2b from below figure

Area b = Area of circular arc(2b+a) - Area of triangle (a+b)

= $$\frac{1}{4}\left(36\pi\ \right)-\ \frac{1}{2}\left(6\times\ 6\right)$$  =$$9\pi\ -18$$

Area of common part of smaller circle = 2b = $$18\pi\ -36$$

Therefore required area = $$576-144\pi+\left(4\times\ 36\pi\right)-8\times\ \left(18\pi\ -36\right)$$

= $$288+144\pi\ $$    

None of the above are correct

Let the point between A and C be D

Triangle ABD and Triangle BCD are congruent using ASA congruency 

Therefore 2x=3y and 4x=5y+10

On solving X=15 and Y=10

Total loss would be = Cost of food + Change that restaurant has  given suresh

= 162+37 + 338+63=600

$$2^x\ +\ 2^x.2\ =48$$

$$2^x\ \left(1+2\right)\ =48$$

$$2^x\ =16$$

x=4

$$4^4=256$$

Total population of A=5000

Population of A below poverty line =16% => population of A above poverty line =  84% = 4200

Number of females above poverty line in A = $$\frac{4}{7}\cdot4200\ =2400$$

Since the individual populations of C and D  aren't given , the number of females below poverty line cannot be determined.

Let total population of C and E be 100x and 100y respectively.

Number of males below poverty line in C = $$\frac{3}{7}\cdot14x$$ = 6x = 6000 => x=1000

Number of males below poverty line in E = $$\frac{4}{5}\cdot25y$$ = 20y=1000=>y= 50

Hence ratio = 20:1

Let total population of F be 100x

Population below poverty line = 20x

Females below poverty line = $$\frac{3}{5}\cdot\ 20x=12x$$ = 16000

=> x= 1333.333

Males below poverty line = $$\frac{2}{5}\cdot\ 20x=8x$$ = 10666.66