Instructions
Following table shows the percentage population of six states below poverty line and proportion of male and female.
Question 149
If the population of males below poverty line in state C is 6000 & state E 1000 then what is the ratio of the total population of state C& E is
Solution
Let total population of C and E be 100x and 100y respectively.
Number of males below poverty line in C = $$\frac{3}{7}\cdot14x$$ = 6x = 6000 => x=1000
Number of males below poverty line in E = $$\frac{4}{5}\cdot25y$$ = 20y=1000=>y= 50
Hence ratio = 20:1
Get AI Help
Create a FREE account and get:
- All Quant Formulas and shortcuts PDF
- 200+ previous papers with solutions PDF
- Top 5000+ MBA exam Solved Questions for Free
SNAP Quant Questions | SNAP Quantitative Ability
SNAP Geometry QuestionsSNAP Inequalities QuestionsSNAP Quadratic Equations QuestionsSNAP Data Sufficiency QuestionsSNAP Progressions and Series Questions
SNAP DILR Questions | LRDI Questions For SNAP
SNAP Verbal Ability Questions | VARC Questions For SNAP
Free SNAP Quant Questions
SNAP Probability, CombinatoricsSNAP Averages, Ratio and ProportionSNAP Data SufficiencySNAP Profit and LossSNAP Time, Speed and DistanceSNAP Functions, Graphs and StatisticsSNAP Linear EquationsSNAP InequalitiesSNAP GeometrySNAP Venn DiagramsSNAP Logarithms, Surds and IndicesSNAP Number SystemsSNAP Progressions and SeriesSNAP Quadratic Equations
