Question 146

If $$2^x + 2^{x + 1} = 48$$, then the value of $$x^x$$ is

Solution

$$2^x\ +\ 2^x.2\ =48$$

$$2^x\ \left(1+2\right)\ =48$$

$$2^x\ =16$$

x=4

$$4^4=256$$

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