SNAP 2013 Question Paper

Let the amount be. Rs x

B's share in the ratio 2:3:4 = $$\ \frac{\ 3}{9}$$ of x=$$\ \frac{\ x}{3}$$

B's share in the ratio 7:2:5 = $$\ \frac{\ 2}{14}$$ of x = $$\ \frac{\ x}{7}$$ , therefore

$$\ \frac{\ x}{3}$$-$$\ \frac{\ x}{7}$$= 40

$$\ \frac{\ 4x}{21}$$ = 40

 x = (40×21)/4 = Rs 210

A is the correct answer.

Number of boys in the school last year = 610

Number of boys in the school in the present year = 610*0.8 (It is given that the boys decreased by 20% this year)

= 488

Number of girls in the class = 1.75* Number of boys 

=1.75*488

=854

A is the correct answer.

Rs.73,689/- are divided between A and B in the ratio 4 :7.

Share of A = $$\ \frac{\ 4}{11}\times\ 73689$$ /- = 26796

Share of B = $$\ \frac{\ 7}{11}\times\ 73689$$ /- = 46893

Now, we have to find the difference between thrice the share of A and twice the share of B 

= 3*26796 - 2*46893 =Rs. 13398

Given, 

Sum of the marks misread = 44+45+61 = 150

Actual marks of the students = 48, 59 and 67

Actual marks sum = 48+59+67 = 174

Difference = 174-150 = 24

Cporrect average = 56+$$\ \frac{\ 24}{24}$$

= 57

D is the correct answer.

Let the present age of Manisha be 5a

The present age of Deepali = Xa

The present age of Praneeta = 5a+9

Praneeta's age after 9 years = 5a+18=33

5a=15

a=3

The difference between Deepali's and Manisha's age is the same as the present age of Parineeta

Xa-5a=5a+9 

3X-15=15+9

3X=39 ==> X=13

D is the correct answer.

1st case :

Distance travelled by train = 300km and by taxi = 200km

Let the speed of train be x km/hr and that of taxi be y km/hr.

Time taken by train = 300/x and time taken by taxi = 200/y hr

$$\ \frac{\ 300}{x}$$ = $$\ \frac{\ 200}{y}$$

Total time taken = 5hrs 30 mins = 5 1/2 hrs

$$\ \frac{\ 300}{x}$$ +$$\ \frac{\ 200}{y}$$= 5$$\ \frac{\ 1}{2}$$

On solving we get : 600y + 400x = 11xy  ----- Eq (1)

2nd case :

Distance travelled by train = 260 km and by taxi = 240 km

The speed of train and taxi will remain the same.

Time taken by train = $$\ \frac{\ 260}{x}$$hr and by taxi = $$\ \frac{\ 240}{y}$$ hr
$$\ \frac{\ 260}{x}$$ + $$\ \frac{\ 240}{y}$$ = 5hrs 36 mins

$$\ \frac{\ 260}{x}$$ + $$\ \frac{\ 240}{y}$$ = 5$$\ \frac{\ 3}{5}$$ on solving we get,

1300y + 1200x = 28xy   ---- Eq (2)

Solving 1 and 2 we get:

x=100 km/hr

Speed of the train = 100km/hr

A is the correct answer.

Let the total work be W units and the number of people employed to do it were 'x'

24*x = 32*(x-9)

3x = 4(x-9)

x=36

$$\therefore$$ Number of people who were supposed to work originally = 36

C is the correct answer.

Profit received by each officer= Rs.25000
Therefore, Profit received by each clerk= $$\ \frac{\ 3}{5}$$×25000 = Rs.15000
Therefore, Total earned profit
= Rs. (45×25000+80×15000)
= Rs.(1125000+1200000)
= Rs.23.25 lakh

D is the correct answer.

Let the cost price of the article be Rs.100x.

Marked price = Rs.130x

S.P. of the article = $$\ \frac{\ 130x\times\ 90}{100}$$ = Rs.117x

Actual percent profit = $$\ \frac{\ 117-100}{100}\times\ 100$$

=17%

D is the correct answer.

The five boys can be arranged on a round table in (5-1)! ways i.e 24

Now there will be five spaces created between two boys.

So three girls can be seated in $$^5C_3$$ ways*3! = 10*6=60

Total number of ways in which five boys and three girls can be seated = 24*60 = 1440

D is the correct answer.