Question 20

There are five boys and three girls who are sitting together to discuss a management problem at a round table. In how many ways can they sit around the table so that no two girls are together?

Solution

The five boys can be arranged on a round table in (5-1)! ways i.e 24

Now there will be five spaces created between two boys.

So three girls can be seated in $$^5C_3$$ ways*3! = 10*6=60

Total number of ways in which five boys and three girls can be seated = 24*60 = 1440

D is the correct answer.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Logical Reasoning Questions SNAP Data Interpretation Questions

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests