MAH MBA CET Sample Paper 2025

The series is third_letter --> fourth_letter --> second_letter --> first_letter.
The third letter, fourth letter and the second letter are in a series while there is a gap of one letter between the first letter and the second letter.
This logic is not followed by option C as there is no gap of 1 letter between O and P.
Hence, C is the answer.

As we know that for making mirror image, We have to rotate entire figure from left to right. After rotation, We got the figure which is given in the option(b).
Hence, option b is the correct answer.

Let H and T be the sets of Hindu and Times of India readers. $$n(H \cup T)=100-6=94=n(H)+n(T)-n(H \cap T)=80+64-x$$. Hence $$x=50$$. $$n(H)=n(H \cap T')+ n(H \cap T)=y+50=64$$. Hence $$y=14.$$

Only Trump is 11
Only Abe is 8
and only Modi is 7
atleast two are invloved in the manufacture of 22 bombs.

So, the total bombs being manufactured = 11 + 8 + 7 + 22 = 48

So, the number of bombs being manufactured by all three together = 48/16 = 3

The number of bombs that Modi and Trump are manufacturing together without Abe is 6.
So, number of bombs that Modi and Abe are preparing without Trump = 20 - 7 - 3 -6 = 4

So, the number of bombs that Abe and Trump are manufacturing together without Modi = 48 - 11 - 8 - 7 - 4 - 6- 3 = 9

Let the number of people who read both the newspapers be x. So, the number of people who read the Hindu but not the Times of India is 28 - x and the number of people who read the Times of India but not the Hindu is 32 - x.
So, total number of people who read at least one newspaper = 28-x + x + 32-x = 60-x.
But, there is no information about the number of people in the locality. So, we cannot determine the value of x.
So, with the information that is available to us, we cannot determine the number of people who read the Time of India but not the Hindu.

We know that
n( A U B ) = n(A) + n( B ) - n (A ∩ B)
=> Here we know that 60 percent students have failed in English and 30 % failed in Hindi. Thus, for passed students we have
n( A U B ) = 60 + 30 - 20
=> n( A U B ) = 70
Hence, 70 % people failed in at least one subject.
Thus, 30 % must have passed in both the subjects.

Following is the correct order of words as found in dictionary-
mild, milieu, militant, military, mindless
Hence, option C is the right answer.

Enthuse

Enthusiastic

Enthusiasm

Enthrall

Enthralled

We need to look after the bold part as the bold part is common to all the words. 

use, usiastic, usiasm, rall, ralled

So, the arrangement would be rall, ralled, use, usiasm, usiastic

Hence, the arrangement would be 4, 5, 3, 2, 1

It is given that C and F are sitting opposite each other. So let’s first place C and F in opposite positions.
Now from statement 2 we know that E is to the immediate left of C.
From statement 1 we know that D and E are neighbours. This means that D must be sitting in between E and F.

Now we know that D is sitting to the immediate right of F.
Hence Option C.

I: The arrangement is either ECA or ACE. Thus, the question can’t be answered from this.
II: Either A is on right end or left end. Again the answer cannot be answered from this alone.
From I and II: Two arrangements are possible.
(i) ACE_ _
(ii) _ _ ECA
We can see that nothing can be said conclusively using even both the information together.