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The cost price of an article is C.P, the selling price is S.P and the marked price is M.P
- Profit (Loss) = S.P – C.P
- % Profit (Loss) = Profit (Loss)/C.P *100
- Discount = M.P – S.P
- % Discount = Discount/M.P * 100
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The cost price of an article is C.P, the selling price is S.P and the marked price is M.P
Formula Video
Amal purchases some pens at ₹ 8 each. To sell these, he hires an employee at a fixed wage. He sells 100 of these pens at ₹ 12 each. If the remaining pens are sold at ₹ 11 each, then he makes a net profit of ₹ 300, while he makes a net loss of ₹ 300 if the remaining pens are sold at ₹ 9 each. The wage of the employee, in INR, is
Correct Answer: 1000
Let the number of pens purchased be n. Then the cost price is 8n. The total expenses incurred would be 8n+W, where W refers to the wage.
Then SP in the first case = $$12\times\ 100+11\times\ \left(n-100\right)$$
Given profit is 300 in this case: 1200+11n-1100-8n-W=300 =>3n-W = 200
In second case: 1200+9n-900-8n-W=-300 (Loss). => W-n = 600.
Adding the two equations: 2n = 800
n = 400.
Thus W = 600 + 400 = 1000
Anil, Bobby, and Chintu jointly invest in a business and agree to share the overall profit in proportion to their investments. Anil’s share of investment is 70%. His share of profit decreases by ₹ 420 if the overall profit goes down from 18% to 15%. Chintu’s share of profit increases by ₹ 80 if the overall profit goes up from 15% to 17%. The amount, in INR, invested by Bobby is
Let the amount invested by Anil Bobby and Chintu be x, y, and z.
Considering x+y+z = 100*p.
Given Anil's share was 70 percent = 70*p.
As per the information provided :
His share of profit decreases by ₹ 420 if the overall profit goes down from 18% to 15%.
Since the profits are distributed in the ratio of their investments :
With a 3% decrease in the profits the value of profit earned by A decreased by Rs 420 which was 70 percent of the total invested.
Hence for all three of them would be combinedly losing $$\left(420\right)\cdot\left(\frac{10}{7}\right)\ =\ 600$$
Hence 3 percent profit was equivalent to Rs 600.
The initial investment is equivalent to Rs 20000.
This is the total amount invested.
Chintu's profit share increased by Rs 80 when the profit percentage increased by 2 %. A 2 percent increase in profit is equivalent to Rs 20000*2/100 = Rs 400.
Of which Rs 80 is earned by Chintu which is 20% of the total Rs 400.
Hence he invested 20% of the total amount.
Bobby invested the other 10 percent.
10 percent of Rs 20000 = Rs 2000
Amal buys 110 kg of syrup and 120 kg of juice, syrup being 20% less costly than juice, per kg. He sells 10 kg of syrup at 10% profit and 20 kg of juice at 20% profit. Mixing the remaining juice and syrup, Amal sells the mixture at ₹ 308.32 per kg and makes an overall profit of 64%. Then, Amal’s cost price for syrup, in rupees per kg, is
Correct Answer: 160
Total syrup - 110 kg
Total juice - 120 kg
It is given, cost price of syrup is 20% less than the cost price of juice.
Let the cost price of juice per kg be 10CP
Cost price of syrup per kg is 8CP
10kg syrup -> cost price = 80CP
It is given, 10kg syrup is sold at 10% profit. This implies selling price = 1.1*80CP = 88CP
20kg juice -> cost price = 200CP
It is given, 20kg juice is sold at 20% profit. This implies selling price = 1.2*200CP = 240CP
It is given, Mixing the remaining juice and syrup, Amal sells the mixture at ₹ 308.32 per kg
Selling price of the remaining mixture = 308.32*200 = Rs 61664
Total S.P = 61664 + 328CP
Total C.P = 880CP + 1200CP = 2080CP
Overall profit = 64%
$$61664+328CP=\frac{164}{100}\left(2080CP\right)$$
Solving, we get CP = 20
Cost price for syrup per kg = 8CP = 8*20 = Rs 160
Gita sells two objects A and B at the same price such that she makes a profit of 20% on object A and a loss of 10% on object B. If she increases the selling price such that objects A and B are still sold at an equal price and a profit of 10% is made on object B, then the profit made on object A will be nearest to
Let us assume the initial selling prices of A and B is p.
Given, she made profit of 20% on A => 1.2 * c = p => c = 5p/6 => cost of A is $$\dfrac{5}{6}p$$
Given, she made a loss of 10% on B => 0.9 * c = p => c = 10p/9 => cost of B is $$\dfrac{10}{9}p$$
Now, she sold them at a price such that a 10% profit is made on B
=> Selling price = s = 11/10 * 10/9 p => $$\dfrac{11}{9}p$$
=> Profit % on A = $$\dfrac{\left(\dfrac{11}{9}-\dfrac{5}{6}\right)}{\left(\dfrac{5}{6}\right)}\times\ 100$$ = 46.66% = nearly 47%
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